General Math MCQs – Basic Algebra (Job Test Preparation in Pakistan)
What is the value of \( x \) in the equation \( 2x + 5 = 11 \)
To find the value of \( x \), subtract 5 from both sides of the equation \( 2x + 5 = 11 \) to get \( 2x = 6 \).
Then, divide both sides by 2 to find \( x = 3 \).
Simplify: \( 3a + 2b - a + 5b \)
Combine like terms to simplify the expression: \( 3a - a + 2b + 5b = 2a + 7b \).
If \( x = 3 \) and \( y = 4 \), what is the value of \( 2x^2 - y \)
Substitute \( x = 3 \) and \( y = 4 \) into the expression \( 2x^2 - y \): \( 2(3)^2 - 4 = 2 \times 9 - 4 = 18 - 4 = 14 \).
What is the solution to \( 5x - 7 = 3x + 5 \)
To solve \( 5x - 7 = 3x + 5 \), first subtract \( 3x \) from both sides to get \( 2x - 7 = 5 \).
Then, add 7 to both sides to get \( 2x = 12 \).
Finally, divide by 2 to find \( x = 6 \).
Factorize: \( x^2 - 9 \)
The expression \( x^2 - 9 \) is a difference of squares, which can be factored as \( (x-3)(x+3) \).
If \( 3x + 4 = 19 \), then \( x = ? \)
To solve \( 3x + 4 = 19 \), first subtract 4 from both sides to get \( 3x = 15 \).
Then, divide both sides by 3 to find \( x = 5 \).
If \( 2a = 8 \), then \( 3a - 5 = ? \)
First, solve \( 2a = 8 \) to find \( a = 4 \).
Then, substitute \( a = 4 \) into \( 3a - 5 \) to get \( 3(4) - 5 = 12 - 5 = 7 \).
Solve: \( \frac{x}{3} + 4 = 10 \)
To solve \( \frac{x}{3} + 4 = 10 \), first subtract 4 from both sides to get \( \frac{x}{3} = 6 \).
Then, multiply both sides by 3 to find \( x = 18 \).
The expression \( (x+2)(x-3) \) expands to:
a)
If \( 4y - 7 = y + 11 \), then \( y = ? \)
To solve \( 4y - 7 = y + 11 \), first subtract \( y \) from both sides to get \( 3y - 7 = 11 \).
Then, add 7 to both sides to get \( 3y = 18 \).
Finally, divide by 3 to find \( y = 6 \).
Simplify: \( \frac{6x^2 y}{3xy} \)
To simplify \( \frac{6x^2 y}{3xy} \), divide the coefficients and subtract the exponents of like bases: \( \frac{6}{3} \cdot x^{2-1} \cdot y^{1-1} = 2x \).
If \( p = 2 \) and \( q = -3 \), then \( p^2 - q^2 = ? \)
Substitute \( p = 2 \) and \( q = -3 \) into the expression \( p^2 - q^2 \): \( (2)^2 - (-3)^2 = 4 - 9 = -5 \).
Solve: \( 2(x - 3) = 10 \)
To solve \( 2(x - 3) = 10 \), first divide both sides by 2 to get \( x - 3 = 5 \).
Then, add 3 to both sides to find \( x = 8 \).
The sum of \( 3x + 5y \) and \( 2x - y \) is:
To find the sum of \( 3x + 5y \) and \( 2x - y \), combine like terms: \( 3x + 2x + 5y - y = 5x + 4y \).
What is the coefficient of \( x \) in \( 5x^2 - 3x + 9 \)
The coefficient of \( x \) in the expression \( 5x^2 - 3x + 9 \) is the number in front of \( x \), which is -3.
If \( \frac{x}{5} = \frac{2}{10} \), then \( x = ? \)
To solve \( \frac{x}{5} = \frac{2}{10} \), simplify the right side to \( \frac{x}{5} = \frac{1}{5} \).
Then, multiply both sides by 5 to find \( x = 1 \).
The product of \( (x+4)(x-4) \) is:
The product \( (x+4)(x-4) \) is a difference of squares, which expands to \( x^2 - 16 \).
Solve: \( 3(2x - 1) = 21 \)
To solve \( 3(2x - 1) = 21 \), first divide both sides by 3 to get \( 2x - 1 = 7 \).
Then, add 1 to both sides to get \( 2x = 8 \).
Finally, divide by 2 to find \( x = 4 \).
If \( a + b = 10 \) and \( a - b = 2 \), then \( a = ? \)
To solve for \( a \), add the two equations \( a + b = 10 \) and \( a - b = 2 \) to get \( 2a = 12 \).
Then, divide by 2 to find \( a = 6 \).
The equation \( 2x + 3 = 3x - 2 \) has the solution:
To solve \( 2x + 3 = 3x - 2 \), first subtract \( 2x \) from both sides to get \( 3 = x - 2 \).
Then, add 2 to both sides to find \( x = 5 \).
The expression \( \frac{2x^3}{8x} \) simplifies to:
To simplify \( \frac{2x^3}{8x} \), divide the coefficients and subtract the exponents of like bases: \( \frac{2}{8} \cdot x^{3-1} = \frac{x^2}{4} \).
The inequality \( 2x - 5 > 7 \) has the solution:
To solve \( 2x - 5 > 7 \), first add 5 to both sides to get \( 2x > 12 \).
Then, divide by 2 to find \( x > 6 \).